Displacement of two light waves are `e_(1)=4 sin omega t and e_(2)= 3 sin (omegat + pi/2)`. so amplitude of resultant wave = .....

Options

A. 0
B. 1
C. 5
D. 7

Answer

C

Explanation

Here `E_(1)=4 and E_(2)=3` and phase difference
Amplitude of resultant wave `delta =(pi)/(2)`
`E=sqrt(E_(1)^(2)+E_(2)^(2)+2E_(1)E_(2) cos delta)`
`=sqrt((4)^(2)+(3)^(2)+2(4)(4)"cos"(pi)/(3)) " " [ :. "cos" (pi)/(2)=0]`
`=sqrt(16+9)= sqrt(25)`
`:.E=5` unit