In Young's experiment distance between `5^(th)` dark fringe and 3rd bright fringe is `x_(5 )-x_(3)=......x

Options

A. 2
B. 3
C. `(2)/(3)`
D. `(3)/(2)`

Answer

D

Explanation

For `5^(th)` dark fringe,
`x_(5)=(9 lambdaD)/(2d) " "...(1)`
For `3^(rd)` bright fringe,
`x_(3)=(3lambdaD)/(d) " "...(2)`
`:.x_(3)-x_(3)=(9 lambdaD)/(2d)-(3lambdaD)/(d)`
`=(3lambdaD)/(2d)=(3)/(2) beta`