In a Young's experiment, the width of one of the two slits is double the other, then interference

Options

A. increases the intensity of bright and dark fringes.
B. The intensity of bright fringes increase and intensity of dark fringes will be zero
C. decreases the intensity of bright fringes and increases the intensity of dark fringes.
D. decreases the intensity of bright fringes and the intensity of dark fringes will be zero.

Answer

A

Explanation

Intensity of light is obtained in the proportional to the width of shit and intensity (amplitude) . The intensity of light at a point by constructive interference due to the superposition of different waves having amplitude `E_(1) and E_(2)`
`I_("max")=(E_(1)+E_(2))^(2)` means increase
and the intensity of light at point due to distractive interference
`I_("min")=(E_(2)-E_(1))^(2) " " "If" E_(1) lt E_(2)`
`=(2E_(1)-E_(1))^(2)`
means intensity of fringes increases.