What will be angle of first order maxima obtained by Fraunhoffer diffraction by single slit of width 0.50 mm , using light of wavelength 500 nm

Options

A. `1.5xx10^(-3)` radian
B. `10.5xx10^(-3)` radian
C. `1xx10^(-3)` radian
D. `3xx10^(-3)` radian

Answer

A

Explanation

Condition for `m^(th)` order maximum
`d sin theta_(m)=(2m+1)(lambda)/(2)`
Taking `m=1`
`sin theta_(1)=(3lambda)/(2d)`
`=(3xx5xx10^(-7))/(2xx5xx10^(-4))=15xx10^(-4)=000015` rad
If `theta_(1)` is too small `sin theta_(1)~~ theta_(1)`
`theta_(1)=0.00015=1.5xx10^(-4)` radian