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In differation angle of first minima of ...

In differation angle of first minima of Fraunhoffer diffraction is `(pi)/(6)` width of slit d =......

A

`lambda`

B

`2lambda`

C

`(lambda)/(2)`

D

`(lambda)/(6)`

Text Solution

Verified by Experts

The correct Answer is:
B
In `d sin theta= n lambda, n=1, theta=(pi)/(6)`
`:. D=((1) lambda)/("sin" (pi)/(6))=( lambda)/((1)/(2))" " :. d=2lambda`
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