In Fraunhoffer diffraction, the wavelength incident light perpendicular to slit made double. the distance from the slit to the screen made tripled and if the width of the slit made `(3)/(2)` times then width of central maximum will be.....

Options

A. three times
B. four times
C. doubled
D. half

Answer

B

Explanation

In diffraction width of central maximum mear distance between two minimum
Width of central maximum `alpha=(2lambdaD)/(d)`
`:.` The new width obtained from modifying I and d,
`alpha.=((2lambda)(3D))/(((3)/(3)))`
`:.(alpha.)/(alpha)=4`
`:.` Four times