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Diameter of lens of telescope is 0.16 m....

Diameter of lens of telescope is 0.16 m. Wavelength of light is 7500Å, so resolving power of telescope will be ..

A

`1.73xx10^(5)`

B

`6.67xx10^(6)`

C

`6.67xx10^(2)`

D

`6.67xx10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
Resolution power of telescope
`=(D)/(1.22 lambda)`
`=(0.61)/(1.22xx75xx10^(-8))`
`=0.00666xx10^(8)`
`=6.67xx10^(5)`
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KUMAR PRAKASHAN-WAVE OPTICS-SECTION-D (MULTIPLCE CHOICE QUESTIONS (MCQS)) (MCQS FROM DARPAN BASED ON TEXTBOOK)
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  2. In telescope, ratio of resolving power due to light of lambda. = 4000Å...

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