The angle of polarisation for any medium is `60^(@)`, what will be the critical angle for this?

Options

A. `sin^(-1)((1)/(sqrt(3)))`
B. `tan^(-1) sqrt(3)`
C. `cos^(-)((1)/(sqrt(3)))`
D. `tan^(-1)((1)/(sqrt(3)))`

Answer

A

Explanation

`u=tan theta_(p)=tan60^(@)`
`:. mu=(1)/(sqrt(3))`
Critical angle,
`sin C=(1)/(mu)=(1)/(sqrt(3))`