When unpolarized light incidents on polarizer 3.14 rad/s angular speed and area 3` xx 10^(-4) m^(2)` with energy `3 * 10^(-3) J`, then find energy of polarized light in each rotation

Options

A. `47.1xx10^(-4)J`
B. `27.1xx10^(-4)J`
C. `37.1xx10^(-4)J`
D. `17.1xx10^(-4)J`

Answer

A

Explanation

`omega=3.14 rad"s^(-1)`
`:.(2pi)/(T)=3.14`
`:.T=(2xx3.14)/(3.14)`
`:. T=2s`
Average intensity
`lt I gt =(I_(0)+0)/(2)=(I_(0))/(2)`
`=(3xx10^(-3))/(3xx10^(-4)xx1xx2)`
`lt I gt -(10)/(2)J`
Energy polarized in each rotation
`E= lt I gt xx "Area" xx` Angular speed
`=(10)/(2)xx3xx10^(-4)xx3.14=47.1xx10^(-4)J`