The critical angular for a particular medium is `sin^(-1)((3)/(5))` , then how much is the angle of polarisation in that medium ?

Options

A. `sin^(-1)((4)/(5))`
B. `tan^(-1)((5)/(3))`
C. `tan^(-1)((3)/(4))`
D. `tan^(-1)((4)/(3))`

Answer

B

Explanation

`theta=sin^(-1)((3)/(5))`
`:.sin theta=(3)/(5)`
`:. (1)/(n)=(3)/(5)` (From total internal reflection)
`:.n=(5)/(3)`
Now from Brewster.s law,
`n=tan theta_(p)`
`:. theta_(p)=tan^(-1)(n)`
`:. theta_(p)=tan^(-1)((5)/(3))`