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At two points P and Q on a screen in Young's double slit experiment, waves from slits `S_(1) and S_(2)` have a path difference of O and `(lambda)/(4)` respectively. The ratio of intensities at P and Q will be ......

A

`3:2`

B

`2:1`

C

`sqrt(3):1`

D

`4:1`

Text Solution

Verified by Experts

The correct Answer is:
B

`I_(P)=I_(0)"cos"^(2){(k(r_(2)-r_(1)))/(2)}`
`=I_(0)cos^(2){K((0)/(2))} " " [ :. r_(2)-r_(1)=0]`
`=I_(0)cos^(2)(0)`
`I_(P)=I_(0) " "…(1)`
`I_(Q)=I_(0)cos^(2){(k(r_(2)-r_(1)))/(2)}`
`=I_(0)cos^(2){(2pi)/(lambda)xx(lambda)/(8)} " " [:.r_(2)-r_(1)=(lambda)/(4)]`
`=I_(0)cos^(2){(pi)/(4)}`
`=I_(0)((1)/(sqrt(2)))^(2)`
`I_(Q)=(I_(0))/(2) " "....(2)`
`:.(I_(p))/(I_(Q))=(I_(0))/(I_(0)/(2))=(2)/(1)`
`:.I_(p)=I_(Q)=2:1`
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