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In a Young's double slit experiment, the...

In a Young's double slit experiment, the separation between the slits is 0.15 mm. In the experiment, a source of light of wavelength 589 nm is used and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is

A

`5.9` mm

B

`3.9` mm

C

`1.9` mm

D

`2.3` mm

Text Solution

Verified by Experts

The correct Answer is:
A

Width of fringe,
`barX=(lambdaD)/(d)`
`=(589x10^(-9)xx1.5)/(1.5xx10^(-4)m)`
`=589xx10^(-5)m`
`=5.89xx10^(-3)m`
`=5.9 mm`
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