In Young's double slit experiment, carried out with light of wavelength `lambda= 5000 Å` the distance between the slits is 0.2 mm and the screen is at 200 cm from the slits. The central maximum is at x = 0. The third maximum (taking the central maximum as zeroth maximum) will be at x equal to ......

Options

A. `1.67 cm`
B. `1.5 cm`
C. `0.5 cm`
D. `5.0 cm`

Answer

B

Explanation

`=x(n) lambda(D)/(d)`
`=3xx5000xx10^(-10)xx(2)/(0.2xx10^(-3))`
`=1.5xx10^(-2)m=1.5 cm`