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A beam of light of lambda= 600 nm from a...

A beam of light of `lambda= 600` nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between first dark fringes on either side of the central bright fringe is ...

A

`1.2` cm

B

`1.2`mm

C

`2.4` cm

D

`2.4` mm

Text Solution

Verified by Experts

The correct Answer is:
D

Condition for first minimum,
`d sin thea_(1)= lambda`
`:. sin theta_(1)=(lambda)/(d)`
but `sin theta_(1)=(x_(1))/(D)`
`:. (x_(1))/(D)=(lambda)/(d)`
`:.x_(1)=(lambdaD)/(d)`
`:.` The distance between first minimum from central maximum on both the sides `=2x_(1)`
`:.2x_(1)=(2lambdaD)/(d)`
`=(2xx600xx10^(-9)xx2)/(1xx10^(-3))`
`=2400xx10^(-6)m=2.4 mm`
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