A proton falls freely under gravity of Earth.Its de-Broglie wavelength after 10s of its motion is ……….Neglect the forces other than gravitational force. (`g=10 m//s^(2),m_(p)=1.67xx10^(-27)Kg,h=6.625xx10^(-34)Js)` [similar as Oct. 2012,'15]

Explanation

From `v=v_(0)+gt`
v=gt
`therefore`Momentum ,p=`m_(p)v=m_(p)gt`
`therefore lambda=(h)/(p)=(h)/(m_(p)"gt")=(6.625xx10^(-34))/(1.67xx10^(-27)xx10xx10)`
`therefore lambda=3.96xx10^(-9)m`