Two particles `A_(1)` and `A_(2)` masses `m_(1),m_(2)(m_(1)gtm_(2))` have the same de-Broglie wavelegth .Then

Options

A. their momenta are the same
B. their energies are the same
C. energy of `A_(1)` is less the energy of `A_(2)`
D. energy of `A_(1)` is more than the energy of `A_(2)`

Answer

A, C

Explanation

According to formula `p=(h)/(lambda)`,since here `lambda` is same,p also would be same.Hence ,option (A) is correct.
Energy of a particle ,`E=(p^(2))/(2m)impliesEprop(1)/(m)`
(`because` p is same )
`impliesE_(1)ltE_(2)(because m_(1)gtm_(2))`
`impliesE_(A_(1))ltE_(A_(2))`