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Work function of metal is phi wavelength...

Work function of metal is `phi` wavelength of incident light is `lambda`.Which condition should be followed for not emitting the photo-electron?

A

`lambdagt(hc)/(phi)`

B

`lambda=(hc)/(phi)`

C

`lambdalt(hc)/(phi)`

D

`lambdale(hc)/(phi)`

Text Solution

Verified by Experts

The correct Answer is:
A
For not emitting the photo-electrons,
`hvltphi`
`therefore (hc)/(lambda)ltphi`
`therefore lambda gt(hc)/(phi)`
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KUMAR PRAKASHAN-DUAL NATURE OF RADIATION AND MATTER-Section-D (multiple choice questions (MCQs)
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  13. If photo-electric effect,when frequency of incident radiation is doubl...

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  14. For metals cesium ,potassium ,sodium and lithium graph of stopping pot...

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  15. Maximum kinetic energy of photoelectron emitted is independent of ……

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  17. Ultraviolet radiation in incident on sodium metal.Then visible light i...

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