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Wavelength of an electron having energy ...

Wavelength of an electron having energy 10 keV ……..Å

A

0.12

B

1.2

C

12

D

120

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda=(h)/(sqrt(2mE))`
`=(6.6xx10^(-34))/(sqrt(2xx9.1xx10^(-31)xx10^(4)xx1.6xx10^(-19)))`
`=0.12xx10^(-10)m`
`therefore lambda=0.12 Å`
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