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Electron starting from rest is acclerate...

Electron starting from rest is acclerated between two point having p.d. of 20 V and 40 V. de-Broglie wavelength of electron……

A

0.75 Å

B

7.5 Å

C

2.75 Å

D

0.75 nm

Text Solution

Verified by Experts

The correct Answer is:
C
Here `V=V_(2)-V_(1)=40-20=20V`
`lambda=(h)/(sqrt(2meV))`
`=(6.62xx10^(-34))/(sqrt(2xx9.1xx10^(-31)xx1.6xx10^(-19)xx20))`
`0.274xx10^(-9)=2.75Å`
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