When de-Broglie wavelength of electron in increased by 1% its momentum…

Options

A. increase by 1%
B. decrease by 1%
C. increase by 2%
D. decreased by 2%

Answer

B

Explanation

`lambda=(h)/(p) therefore lambdaprop (1)/(p)therefore lambda prop p^(-1)`
`dlambda prop -p^(2)dp therefore d lambda prop -(1)/(p^(2))dp`
`therefore (dlambda)/(lambda)xx100=-(dp)/(p^(2))xxpxx100`
`therefore (dp)/(p)xx100=-1%`
`therefore` Momentum will decrease by 1%