A proton moves with speed `(c )/(10)`.Its de-Broglie wavelength will be……
`(h=6.63xx10^(-34)Js,m_(p)=1.673xx10^(-27)Kg)`

Options

A. 0.1321 Å
B. 1.321 Å
C. `0.1321xx10^(-2)Å`
D. `1.321xx10^(-4)Å`

Answer

D

Explanation

`p=(h)/(lambda)=m_(p)v`
`therefore lambda =(h)/(m_(p)v)`
but `v=(c )/(10)=(3xx10^(8))/(10)=3xx10^(7) m//s` and
`m_(p)=1.0078xx1.66xx10^(-27)`kg
`-1.673xx10^(-27)kg`
`therefore lambda=(6.63xx10^(-34))/(1.673xx10^(-27)xx3xx10^(7))`
`=1.321xx10^(-14)m`
`=1.321xx10^(-4)Å`