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If electron is accelerated under 50 KV i...

If electron is accelerated under 50 KV in microscope ,find its de-Broglie wavelength.

A

`5.485xx10^(-12)m`

B

`8.545xx10^(-12)m`

C

`4.585xx10^(-12)m`

D

`5.845xx10^(-12)m`

Text Solution

Verified by Experts

The correct Answer is:
A
V=50 KV =`50xx10^(3)V`
`lambda=(h)/(sqrt(2meV))`
`=(6.62xx10^(-34))/(sqrt(2xx9.1xx10^(-31)xx50xx10^(3)xx1.6xx10^(-19)))`
`=(6.62xx10^(-34))/(1.207xx10^(-22))`
`5.485xx10^(-12)m`
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