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Uncertainty of momentum of a particle is...

Uncertainty of momentum of a particle is `10^(-30) kg ms^(-1)`,minimum uncertainty in its position will be……..

A

`10^(-8)m`

B

`10^(-12)m`

C

`10^(-16)m`

D

`10^(-4)m`

Text Solution

Verified by Experts

The correct Answer is:
D
`Deltax.Deltap=(h)/(2pi)`
`therefore Deltax=(h)/(2piDeltap)`
`=(6.62xx10^(-34))/(6.28xx10^(-30))=1.054xx10^(-4)m~~10^(=-4)m`
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