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Energy corresponding to threshold freque...

Energy corresponding to threshold frequency of metal is 6.2 eV.For given radiation stopping potential is 5 V then incident radiation will be in …region.

A

X-ray

B

ultraviolet

C

infrared

D

visible

Text Solution

Verified by Experts

The correct Answer is:
B
`E=K_(m)+phi=eV_(0)+phi=(5+6.2)eV=11.2 eV`
`(hc)/(lambda)=11.2xx1.6xx10^(-19)J`
`therefore lambda =(6.62xx10^(-34)xx3xx10^(8))/(11.2xx1.6xx10^(-19))`
`=1.108xx10^(-7)m=1108 Å`
This wavelength is in ultraviolet region.
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