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Momentum of photon with frequency f wil...

Momentum of photon with frequency f will be …..(where c is velocity of light)

A

`(hf)/(c^(2))`

B

hfc

C

`(f)/(c)`

D

`(hf)/(c )`

Text Solution

Verified by Experts

The correct Answer is:
D

Momentum of photon `p=(h)/(lambda)=(hf)/(c )[because (1)/(lambda)=(f)/(c )]`
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Knowledge Check

  • Momentum of photon having 1 MeV energy is

    A
    `7xx10^(-24)`
    B
    `10^(-22)`
    C
    `5xx10^(-22)`
    D
    `0.33xx10^(6)`
  • Energy of n photon having frequency v is……

    A
    `nhv^(2)`
    B
    `(nh)/(v)`
    C
    nhv
    D
    `(hv)/(n)`
  • The speed of an electron in first Bohr orbit is (c )/(137) , where c is the velocity of light in vacuum, then the speed of electron in second orbit is …………..

    A
    `(1)/(2)((c)/(137))`
    B
    `2((c)/(137))`
    C
    `(1)/(4)((1)/(137))`
    D
    `(1)/(4)((1)/(137))`
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