A source `S_(1)` produces `10^(15)` photon every second having wavelength of 5000Å .Another source `S_(2)` produce `1.02xx10^(15)` photon every second with wavelength 5100 Å product [Power of `S_(1)`]`xx`[Power of `S_(2)`]=….

Options

A. `1.00`
B. `1.02`
C. `1.04`
D. `0.98`

Answer

A

Explanation

Energy produced every second by `S_(1)` (power)
`P_(1)=n_(1)(hc)/(lambda_(1))`
Energy produced every second by `S_(2)` (Power)
`P_(2)=n_(2)(hc)/(lambda_(2))`
`therefore (P_(2))/(P_(1))=(n_(2))/(n_(1))xx(lambda_(1))/(lambda_(2))`
`=(1.02xx10^(15))/(10^(15))xx(5000)/(5100)=1.0`