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The threshold frequency for a certain me...

The threshold frequency for a certain metal is `3.3xx10^(14)` Hz.If light of frequency `8.2xx10^(14)`Hz is incident on the metal ,predict the cutoff voltage for the photoelectric emission.

A

2 V

B

3 V

C

5 V

D

1 V

Text Solution

Verified by Experts

The correct Answer is:
A
`KE=hf-hf_(0)=eV_(0)` (where `V_(0)` is cutoff voltage)
`impliesV_(0)=(h)/(e )(8.2xx10^(14)-3.3xx10^(14))`
`=(6.6xx10^(-34)xx4.9xx10^(14))/(1.6xx10^(-19))~~2V`
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