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In an experiment on photoelectric effect...

In an experiment on photoelectric effect the stopping potentail was measured to be `V_(1)` and `V_(2)` with incident light of wavelength `lambda` and `(lambda)/(2)` respectively.The relation between `V_(1)` and `V_(2)` is….

A

`V_(2)gt2V_(1)`

B

`V_(2)ltV_(1)`

C

`V_(2)ltV_(2)lt2V_(1)`

D

`V_(2)=2V_(1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`V_(1)=(hc)/(elambda)-(phi)/(e )implies(hc)/(elambda)=V_(1)+(phi)/(e)implies(2hc)/(elambda)=2V_(1)+(2phi)/(e )`
`V_(2)=(2hc)/(elambda)-(phi)/(e )-(2hc)/(elambda)=V_(2)+(phi)/(e )`……(2)
Equation (1) and (2) are same .
`therefore V_(2)+(phi)/(e )=2V_(1)+(2phi)/(e )`
`therefore V_(2)=2V_(1)+(phi)/(e)`
`therefore V_(2)gt2V_(1)`
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