When kinetic energy of proton is equal to energy of photon then ratio of de-Broglie wavelength of proton and photon is proportional to …..

Options

A. E
B. `E^(-(1)/(2))`
C. `E^((1)/(2))`
D. `K_(2)=2K_(1)`

Answer

C

Explanation

For photon `lambda_(p)=(hc)/€`
Where E is energy of photon
For ptoyon `lambda_(p)=(h)/(sqrt(2mK))`
here m and K are mass and kinetic energy of proton ,
`therefore (lambda_(p))/(lambda_(p))=(E )/(c )sqrt(2mK) propE^((1)/(2))[because E=K]`