When monochromatic light of frequency `f_(1)` incident on photosensitive surface ,stopping potential obtained is `V_(1)`.When same surface is incident with monochromatic light of frequency `f_(2)` is incident on same surface ,stopping potential will become......

Options

A. `V_(1)+(h)/(e )(f_(2)-f_(1))`
B. `V_(1)-(h)/(e )(f_(2)-f_(1))`
C. `V_(1)+(h)/(e )(f_(1)+f_(2))`
D. `V_(1)-(h)/(e )(f_(1)+f_(2))`

Answer

A

Explanation

`eV_(1)=hf_(1)-phi` and `eV_(2)=hf_(2)-phi_(0)`
`e(V_(2)-V_(1))=h(f_(2)-f_(1))`
`therefore V_(2)-V_(1)=(h)/(e )(f_(2)-f_(1))`
`therefore V_(2)=V_(1)+(h)/(e )+(h)/(e )(f_(2)-f_(1))`