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For given metal work function is W(0) an...

For given metal work function is `W_(0)` and threshold wavelength is `lambda_(0)`.If metal has work function `(W_(0))/(2)` then what will be threshold wavelength ?

A

`(lambda_(0))/(4)`

B

`(lambda_(0))/(2)`

C

`2lambda_(0)`

D

`4lambda_(0)`

Text Solution

Verified by Experts

The correct Answer is:
C

`W_(0)=(hc)/(lambda_(0))` and `W_(0)=(hc)/(lambda_(0))`
`therefore (W_(0))/(W_(0))=(lambda_(0))/(lambda_(0))`
`(W_(0))/(W_(0))=(lambda_(0))/(lambda_(0))`
`(W_(0))/((W_(0))//(2))=(lambda_(0))/(lambda_(0)) [because W_(0)=(W_(0))/(2)]`
`therefore 2lambda_(0)=lambda_(0)`
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