If particle mentioned below moves with same velocity which will have highest de-Broglie wavelength ?

Options

A. Neutron
B. Proton
C. `beta`-particle
D. `alpha`-particle

Answer

C

Explanation

From de-Broglie wavelength `lambda=(lambda)/(P)=(lambda)/(mv)`
`lambda prop (1)/(m)`
Particle with least mass will have maximum de-Broglie wavelength.Here ,`beta`-particle (electron) has least mass hence its de-Broglie wavelength will be maximum