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Photons of energy 1 eV and 2.5 eV sucess...

Photons of energy 1 eV and 2.5 eV sucesseively illuminate a metal,whose work function is 0.5 eV,the ratio of maximum speed of emitted electron is…..

A

`1:2`

B

`3:1`

C

`2:1`

D

`1:3`

Text Solution

Verified by Experts

The correct Answer is:
A
`((1)/(2)mv_(max)^(2))_(2)=(hf)_(2)-phi=2.5-0.5=2.0 eV`
`((1)/(2)mv_(max)^(2))_(2)=(hf)_(2)-phi=2.5-0.5=2.0eV`
`therefore ("Ratio")^(2)=(0.5)/(2)=(1)/(4)`
`therefore ((v_(max))_(1))/((v_(max))_(2))=(1)/(2)`
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