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If an LED has to emit 662 nm wavelength ...

If an LED has to emit 662 nm wavelength of light then what should be the band gap energy of its semiconductor? `(h=6.62xx10^(-34)Js)`

Text Solution

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`lambda=662xx10^(-9)m`
`=6.62xx10^(-7)m`
`h=6.62xx10^(-34)J`
`lambda=(hc)/(E_(g))`
`E_(g)=(hc)/(lambda)`
`=(6.62xx10^(-34)xx 3 xx10^(8))/(6.62xx10^(-7))`
`therefore E_(g)=3xx10^(-19)J`
`therefore E_(g)=(3xx10^(-19))/(1.6xx10^(-19)) therefore E_(g)=1.875 eV`
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