The output of the given circuit in figure.

Options

A. would be zero at all times.
B. would be like a half wave rectifier with positive cycles in output.
C. would be like a half wave rectifier with negative cycles in output.
D. would be like that of a full wave rectifier.

Answer

C

Explanation

would be like a half wave rectifier with negative cycles in output.

In above circuit, when a is positive with respect to b, diode is in forward bias condition and so taking its resistance zero, output voltage
`V_(0)=V_(d )-V_(c )=0`
In above circuit, when a is negative with respect to b, diode is reverse biased and so taking its resistance infinite, current becomes zero and so,
`V_(a)=V_(d )`
`therefore V_(a)-V_(b)=V_(d)-V_(b)`
`therefore V_(a)-V_(b)=V_(d)-V_(c )" "(because V_(b)=V_(c ))`
`therefore V_(a)-V_(b)=V_(0)`
`therefore V_(0) lt 0 " " (because V_(a) lt V_(b))`
Thus, for each positive half cycle of A.C. supply, `V_(0)=0` and for each negative half cycle of A.C. supply `V_(0)` remains negative. Hence, output voltage will be like output voltage of half wave rectifier with alternative negative half cycles.