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Draw the output waveform across the resi...


Draw the output waveform across the resistor.

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Here, current passing through the closed path given in the statement,
`I=(v_(i))/(R+R_(D))" "…(1)`
(where `R_(D)=` resistance of diode)
During negative half cycle of input voltage, since diode is reverse biased, `R_(D)=oo` and so from equation (1), I = 0 and so output voltage
`v_(0)=IR=0 " "(because I=0)`
During positive half cycle of input voltage, since diode is forward biased , `R_(D)=0` and so from equation (1), `I=(v_(i))/(R )` and so output voltage `v_(0)=IR =((v_(i))/(R ))R=v_(i)=1` volt. (from figure)
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