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In the circuit shown in figure, when the...


In the circuit shown in figure, when the input voltage of the base resistance is 10V, `V_(BE)` is zero and `V_(CE)` is also zero. Find the values of `I_(B), I_(C ) and beta`.

Text Solution

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In the input section,
`v_(i)=I_(B)R_(B)+V_(BE)`
`therefore 10=(I_(B))(400xx10^(3))+0`
`therefore I_(B)=(10)/(400xx10^(3))=0.25xx10^(-4)A`
`therefore I_(B)=25xx10^(-6)A=25muA`
In the output section,
`V_(C C)=I_(C )R_(C )+V_(CE)`
`therefore10=I_(C )(3xx10^(3))+0`
`therefore I_(C )=(10)/(3xx10^(3))=0.3333xx10^(-2)A`
`therefore I_(C )=3333xx10^(-6)A=3333muA`
`rArr beta=(I_(C ))/(I_(B))=(3333)/(25)=133.3`
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