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In pure crystal of silicon at 300 K temp...

In pure crystal of silicon at 300 K temperature having number of atom `n_(i)=10^(16)m^(-3)`. If `10^(21)` atoms of phosphorus added per `m^(3)` then number of holes created will be …… /`m^(3)`.

A

`10^(21)`

B

`10^(19)`

C

`10^(11)`

D

`10^(5)`

Text Solution

Verified by Experts

The correct Answer is:
C
`10^(11)`
`n_(i)^(2)=n_(e )n_(n)`
`therefore n_(n)=(n_(i)^(2))/(n_(e ))=((10^(16))^(2))/(10^(21))=10^(11)m^(-3)`
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