Therefore are `6xx10^(19)` electrons per unit cubic metre of pure semiconductor. What will be the number of holes for this semiconductor of dimension `1 cm xx 1 cm xx 2 cm`?

Options

A. `6xx10^(19)`
B. `1.2xx10^(14)`
C. `12xx10^(14)`
D. `2xx10^(6)`

Answer

B

Explanation

`1.2xx10^(14)`
Volume of crystal `v=l xx b xx h`
`=1xx1xx2xx10^(-6)m^(3)`
`=2xx10^(-6)m^(3)`
In pure semiconductor `n_( e)=n_(h)=6xx10^(19)m^(-3)`
`therefore` Total number of holes in crystal,
`N=n_( e)V=6xx10^(19)xx2xx10^(-6)=12xx10^(13)`