An A.C. supply of 350 V, 60 Hz is applied to a full wave rectifier. If internal resistance of each diode is `200Omega` and load resistance `R_(1)=5k Omega`, then the maximum value of output current is …….

Options

A. 0.065 A
B. 0.092 A
C. 0.095 A
D. 0.07 A

Answer

B

Explanation

0.092 A
`I_(m)=I_("rms")xx sqrt(2)`
`=(V_("rms")xx sqrt(2))/(R_(2)+2r_(f))`
where `r_(f )=` resistance of diode in forward bias
`=(350xx1.414)/(5000+2xx200)=0.0916A`
`therefore I_(m)~~0.092A`