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For common emitter configuration, if alp...

For common emitter configuration, if `alpha and beta` have their usual meanings, the incorrect relationship between `alpha and beta` is :

A

`(1)/(alpha)=(1)/(beta)+1`

B

`alpha=(beta)/(1-beta)`

C

`alpha=(beta)/(1+beta)`

D

`alpha=(beta^(2))/(1+beta^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

`(B) alpha=(beta)/(1-beta) (D) alpha=(beta^(2))/(1+beta^(2))`
For transistor `I_(E )=I_(B)+I_(C )`
`therefore (I_(B))/(I_(C ))=(I_(B))/(I_(C ))+1`
`therefore (1)/(alpha)=(1)/(beta)+1" "`(Option (A) is correct)
`therefore (1)/(alpha)=(1+beta)/(beta)`
`therefore alpha=(beta)/(1+beta)" "` (Option C is correct)
`therefore` Option (B) and (D) are not correct.
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KUMAR PRAKASHAN-SEMICONDUCTOR ELECTRONICS : MATERIALS, DEVICES AND SIMPLE CIRCUITS -Section-D : Multiple Choice Questions (MCQs) (MCQs asked in Competitive Exams)
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