In the circuit shown in figure, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is

Options

A. zero
B. 5 mA
C. 9 mA
D. 14 mA

Answer

C

Explanation

9 mA
If current passing through `10kOmega` is `I_(2)`, then
`I_(2)=(50)/(10xx10^(3))=5mA`
If current passing through `5kOmega` is I, then
`I=((120-50))/(5xx10^(3))=(70)/(5)xx10^(-3)A`
`therefore I=14mA`
If current passing through zener diode is `I_(1)`, then
`I_(1)=I-I_(2)`
`=(14-5)mA`
`therefore I_(1)=9mA`