In the circuit shown in figure, when the input voltage of the base resistance is 10V, `V_(BE)` is zero and `V_(CE)` is also zero. Find the values of `I_(B), I_(C ) and beta`.

Options

A. `I_(B)=40muA, I_(C )=5 mA, beta=125`
B. `I_(B)=40muA, I_(C )=10 mA, beta=250`
C. `I_(B)=20muA, I_(C )=5 mA, beta=250`
D. `I_(B)=25muA, I_(C )=5 mA, beta=200`

Answer

A

Explanation

`I_(B)=40muA, I_(C )=5 mA, beta=125`
`V_(i)=I_(B)R_(B)+V_(BE)`
`20=I_(B)xx500xx10^(3)+0`
`therefore I_(B)=(20)/(5xx10^(5))`
`I_(B)=4xx10^(-5)`
`=40xx10^(-6)A`
`therefore I_(B)=40muA`
Now `beta=(I_(C ))/(I_(B))`
`=(5xx10^(-3))/(40xx10^(-6))`
`therefore beta =125`
`therefore V_(C C)=I_(C )R_(C )+V_(CE)`
`20=I_(C )xx4 xx 10^(3)+0`
`therefore I_(C )=(20)/(4xx10^(3))`
`therefore I_(C )=5 mA`