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The wavelength of photon having energy o...

The wavelength of photon having energy of 35 keV is ……..
`(h=6.625xx10^(-34)J-s, c=3xx10^(8)ms^(-1), 1eV=1.6xx10^(-19)J)`.

A

`35xx10^(-12)m`

B

35 Å

C

3.5 nm

D

3.5 Å

Text Solution

Verified by Experts

The correct Answer is:
A
`35xx10^(-12)m`
`E=hf=(hc)/(lambda)`
`therefore lambda=(hc)/(E )`
`=(6.625xx10^(-34)xx3xx10^(8))/(35xx10^(3)xx1.6xx10^(-19)) `
`=0.3549xx10^(-10)m`
`=35.49xx10^(-12)m`
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