A current of 5.0 A is passed through the coil of a galvanometer having 500 turns and each turns has an average area of `3xx10^(-4) m^(2)` if a torque of 1.5 N-m is required for this coil carrying same current to set it parallel to a magnetic field calculate the strength of the magnetic field

A current of 0.5 A is passed through the coil of a galvanometer having 500 turns and each turns has an average area of 3xx10^(-4) m^(2) if a torque of 1.5 N-m is required for this coil carrying same current to set it parallel to a magnetic field calculate the strength of the magnetic field

A current of 0.5 A is passed through the coil of a galvanometer having 500 turns and each turns has an average area of 3xx10^(-4) m^(2) if a torque of 1.5 N-m is required for this coil carrying same current to set it parallel to a magnetic field calculate the strength of the magnetic field

The coil of a galvanometer has 500 turn and each turn has an average area of 3 xx 10^(-4) m^(2) . Calculate the magnetic moment of the coil when a current of 0.5 A passes through it. If a torque of 1.5 Nm is required for this coil carrying same current to set it parallel to a magnetic field. calculate the strength of the magnetic field.

A circular coil of radius 10 cm having 100 turns carries a current of 3.2 A. The magnetic field at the center of the coil is

A circular coil of radius 10 cm having 100 turns carries a current of 3.2 A. The magnetic field at the center of the coil is

A current of 2 ampere is flowing through a coil of radius 0.1 m and having 10 turns. The magnetic moment of the coil will be :

A circular coil of 0.2 m diameter has 100 turns and carries a current of 0.1 ampere. The intensity of magnetic field at the centre of the coil is -

A 100 turns coil shown in figure carries a current of 2 amp in a magnetic field B=0.2 Wb//m^(2) . The torque acting on the coil is