" द्ध कीजिए कि: "x=(pi)/(3)" पर "sin x(1+cos x)" उच्चष्ठ है। "

If sin^(-1)x=(pi)/(3) then cos^(-1)x

If sin^(-1)x=(pi)/(3) then find cos^(-1)x

lim_(x rarr pi/3) (sin (pi/3-x))/(2 cos x-1) =

The solution set of "sin" (x - (pi)/(4))-"cos" (x + (3 pi)/(4)) =1 " and " (2 "cos" 7x)/("cos" 3 + "sin" 3) gt 2^("cos" 2x) , is

The solution set of "sin" (x - (pi)/(4))-"cos" (x + (3 pi)/(4)) =1 " and " (2 "cos" 7x)/("cos" 3 + "sin" 3) gt 2^("cos" 2x) , is

lim_(x rarr pi//3) (2 sin (x-pi//3))/(1-2 cos x) equals :

If sin ^ (- 1) x + sin ^ (- 1) y = (2 pi) / (3), then cos ^ (- 1) x + cos ^ (- 1) y =

Find the number of solutions of the equations (sin x - 1)^(3) + (cos x - 1)^(3) + ( sin x)^(3) = ( 2 sin x + cos x - 2)^(3) in ( 0, 2 pi) .