सैल में होने वाली निम्न रिडॉक्स अभिक्रिया ,
`Zn(s)+Cu^(2+)(0.1M)to Zn^(2+)(1M)+Cu(s)`
के लिए `E_("सैल")^(@) 1.10V` है । सैल के लिए `E_("सैल") (2.303(RT)/(F)=0.0591)` होगा -

For the redox reaction: Zn(s) +Cu^(2+) (0.1M) rarr Zn^(2+) (1M)+Cu(s) taking place in a cell, E_(cell)^(@) is 1.10 volt. E_(cell) for the cell will be (2.303 (RT)/(F) = 0l.0591)

For the redox reaction: Zn(s) +Cu^(2+) (0.1M) rarr Zn^(2+) (1M)+Cu(s) taking place in a cell, E_(cell)^(@) is 1.10 volt. E_(cell) for the cell will be (2.303 (RT)/(F) = 0l.0591)

For the redox reaction: Zn(s)+Cu^(2+) (0.1M) rarr Zn^(2+) (1M) + Cu(s) taking place in a cell, E_(cell)^(@) is 1.10V. E_(cell)^(@) for the cell will be [2.303(RT/F)=0.0591]

Consider the following reaction, Zn(s)+Cu^(2+) (0.1 M) rarr Zn^(2+) (1 M)+Cu(s) above reaction, taking place in a cell, E_("cell")^(@) is 1.10 V. E_("cell") for the cell will be (2.303 (RT)/(F)=0.0591)

Consider the following reaction, Zn(s)+Cu^(2+) (0.1 M) rarr Zn^(2+) (1 M)+Cu(s) above reaction, taking place in a cell, E_("cell")^(@) is 1.10 V. E_("cell") for the cell will be (2.303 (RT)/(F)=0.0591)