int_(0)^( pi/4)sqrt(1-sin2x)dx

" (a) "int_(0)^( pi/6)sqrt(1-sin2x)dx" का मान ज्ञात कीजिए "

int_(0)^( pi/2)sqrt(1-sin x)dx

int_(0)^(pi/2)sqrt(1-sin2x)dx is equal to

Evaluate: int_0^(pi//4)sqrt(1-sin^2x)dx

int_(0)^(pi//4)[sqrt([1-sin2x)/(1+sin2x)]dx=

int_(0)^(pi//4)sqrt((1-sin2x)/(1+sin 2x))dx=

int_(0)^( pi//2)sqrt((1-sin2x)/(1+sin2x))dx

Match the following. {:(I,int_(0)^(pi//2)sqrt(1-cos2x)dx=,(a),2),(II,int_(0)^(pi//2)sqrt(1+sin2x)dx=,(b),sqrt2),(III,int_(0)^(1)(x)/(1+x^(2))dx=,(c),log2),(IV,int_(0)^(pi//2)(cosx)/(1+sinx)dx=,(d),(1)/(2)log2):}