Calculate spin magnetic momentum of `M_((aq))^(+2)` ions. (Z=26)

Options

A. 4.89 BM
B. 0.489BM
C. 48.9BM
D. 489BM

Answer

A

Explanation

Here, atomic number Z=26
So, for M ions `= [Ar] 3d^(6) 4s^(2)`
So, for `M^(+2)` ions `= [Ar] 3d^(6) 4s^(0)`

Here, unpaired electrons are 4.
`:.` Magnetic momentum `mu= sqrt(n(n+2))`
`=sqrt(4(4+2)) = 4.89BM`