The rate constant for a second order reaction is given by `k=(5 times 10^11)e^(-29000k//T)`. The value of `E_a` will be:

The rate constant of a first order reaction is given by K=2.1xx10^(10)"exp"(-2700//T) . It meas that

The rate constant of a certain reaction is given by: log k= 5.4-(212)/(T)+2.17 log T Calculate E_(a) at 127^(@)C .

The rate constant of a certain reaction is given by: log k= 5.4-(212)/(T)+2.17 log T Calculate E_(a) at 127^(@)C .

The rate constant of a reaction at 298 K is given by 3.2xx10^(-3)s^(-1) .Find the order of reaction?

A reaction rate constant is given by k = 1.2 xx 10^(14) e^((-2500)/(RT))s^(-1) . It means

A reaction rate constant is given by k = 1.2 xx 10^(14) e^((-2500)/(RT))s^(-1) . It means

The rate constant K_(1) and K_(2) for two different reactions are are 10^(16)e^(-2000//T) and 10^(15)e^(-1000//T) , respectively. The temperature at which K_(1)=K_(2) is